I Need Some Help to Solve an Interesting Lunar Puzzle

The Conundrum

[N.B. A Full Moon Cycle (FMC = 411.78443025 days epoch J2000.0) is the time required for the Sun (as seen from the Earth) to complete one revolution with respect to the Perigee of the Lunar orbit. In other words, it is the time between repeat occurrences of the Perigee end of the lunar line-of-apse pointing at the Sun. The value for the length of the FMC is equal to the synodic product of the Synodic (lunar phase) month (= 29.530588853 days) with the anomalistic month (= 27.554549878 days) for Epoch J2000.0. The anomalist month is the time required for the Moon to return to the Perigee of the lunar orbit.]  

[N.B. The Lunar Anomalistic Cycle (LAC = 3232.60544062 days = 8.85023717 sidereal years) is the time required for the lunar line-of-apse to precess once around the sky with respect to the stars. This corresponds to a 0.11136528^O per day movement of the lunar line-of-apse in a pro-grade (clockwise) direction. The value for the length of the LAC is equal to the synodic product of the anomalistic month (= 27.554549878 days) with the sidereal lunar month (= 27.231661547 days) for Epoch J2000.0. The sidereal month is the time required for the Moon to rotate once around its orbit with respect to the stars.]  

The diagram below shows the Perigee of the lunar orbit pointing at the Sun at 0.0 days. In addition, the diagram shows the Perigee of the lunar orbit once again pointing at the Sun after one Full Moon Cycle (FMC) = 411.78443025 days. It takes more than 1.0 sidereal year (= 365.256363004 days) for the Perigee to realign with the Sun because of the slow pro-grade (clockwise) precession of the lunar line-of-apse once every 8.85023717 sidereal years.

1.0 FMC falls short of 15 anomalistic months (= 413.31824817 days) by 1.53381792 days (= 1.5117449198^O). During these 1.5117449198 days the Perigee end of the lunar line-of-apse rotates by 0.17081406^O in a prograde direction, producing an overall movement of the line-of-apse (red line) of 1.34093086^O (= 1.5117449198^O – 0.17081406^O) with respect to the Earth-Sun line (blue line).

if we let:

  DT  =  (15 anomalistic months -- FMC) = (413.31824817 -- 411.78443025) days 

         = 1.53381792 days

      S = the angular revolution (in degrees) of the Earth about the Sun over DT days.

          = 1.5117449198 degrees

      L = the orbital precession (in degrees) of the lunar line-of-apse over DT days.

          = 0.1708140574 degrees

then  

      D = S -- L = angle between the lunar line-of-apse and the Earth-Sun line after DT days.

          = 1.3409308624 degrees

we find that if we take the incremental angle between the lunar line-of-apse and the Earth-Sun line over DT days (= 1.3409308624 degrees) and divide it by the 360 degrees of movement of the angle between the lunar line-of-apse and the Earth-Sun line that has occurred over the previous FMC, it effectively has the same value as the incremental number of days between 15 anomalistic months and 1.0 FMC (=1.5338172 days) divided by 1.0 FMC i.e.    

     (S -- L) / 360 degrees = (15 anomalistic months - FMC) / FMC = 0.0037248080            (1)

While this is not remarkable, what is remarkable, however, is that both of these fractions (whether they be measured in degrees or days) are precisely equal to the cumulative annual precession of the Perihelion of the Earth's orbit (measured in days) over a period of 1.0 FMC!

= (11.723"/3600) deg. per yr x (365.256363004 days / 360 deg.) x (411.78443025 / 365.256363004)

= 0.0037248062 days per 1.127384686 sidereal years.

N.B. The current value for the precession of the Perihelion of the Earth's orbit is 11.615 arc seconds per year. However it is increasing and will achieve a value of 11.723 arc seconds in roughly 2490 A.D.   

Here's the Rub [updated 25/04/2017]

1. The cumulative precession of the Earth's orbit over a period of 1.0 FMC has the dimensions of days per year!

I must be missing something. Why the strange units of days per 1.127384686 sidereal years? Can anyone help me understand why I get these weird dimensionless units? [updates 22/04/2017]

2.  The increase in angle between the lunar line-of-apse and the Earth-Sun line as you move from 1.0 FMC to 15 anomalistic months (= 1.34093086 degrees) seems to be almost precisely equal to the FULL annual precession of the Perihelion of the Earth's orbit (= 11.723 arc seconds per year) PER DAY accumulate over 1.0 FMC i.e.

[(11.723 / 3600) deg per YEAR] x 411.78443025 days = 1.34093024 degrees

The question is, what angular motion associated with the movements in Sun-Earth-Moon system can cause the ANNUAL precession of the Perihelion of the Earth's orbit to accumulate DAILY?

I am not aware of any mechanism that would produce a motion like this and I would appreciate if anyone could solve this interesting lunar puzzle for me!

Is it something to to do with the interaction between the mean and true anomalies of the Earth's orbit and the Moon's orbit? Could motion of the Earth and moon about the common centre-of-gravity have and effect? What about the effects of 18.6 year nutation of the Earth's rotation axis?

THANKS IN ADVANCE